p4 clients -u
Categories
FollowersBlog Archive
Jobs
Find more freelance jobs
|
Tuesday, May 21, 2013Deleting all your perforce workspacesp4 clients -u Tuesday, May 8, 2012‘xterm-256color’: unknown terminal type...
solving this error on Mac OSX Lion is simple.
Running “sudo apt-get install ncurses-term” will get rid of this error. Tuesday, October 18, 2011Given a dependency list of the components, how do you find the correct build order in MakeFile
This problem can be mapped to the Topological sorting of vertices in a graph assuming each component as the vertice in the graph and edge as the dependency indicator.For more details see the link below.
http://en.wikipedia.org/wiki/Topological_sorting Unix have tsort program for doing the same. For a DAG(directed acyclic graph) tsort produces a listing of the vertices so that for all edges 'a->b', 'a' comes before 'b' in the listing. This is used in MakeFile for identifying the build order of the components in a way to fulfill dependencies. This will not work when the graph have cycles. (Cyclic dependencies are not taken care). http://en.wikipedia.org/wiki/Tsort_%28Unix%29 Saturday, August 20, 2011Saturday, August 6, 2011Monday, January 24, 2011Very good resource for algorithms
If you are planning to learn all algorithms in a systematic way, you can visit this site.
http://www.allisons.org/ll/AlgDS/Glossary/ Good thing about this site is it outlines fundamental concept of data structure or algo with example and gives some practical use cases also. Sunday, December 19, 2010My new blog for android users
Hi Friends,
I recently started writing my experiments with android. You can find the link below. http://indiandroidism.blogspot.com/ Sunday, November 21, 2010100 coins dividing into equal heads groups.
Question:
You have 100 coins, 37 of them are heads, rest are tails. Your task is to divide this 100 coins into two groups in which there will be the same number of heads. You are blindfolded and you can flip any number of coins. Solution: Pick any 37 coins and flip all of them. Explanation: Lets take a simple case where 5 coins with 3 heads and 2 tails. HTHHT Lets take 3 coins randomly. Say first,fouth and fifth lets call it S1. Let remaining coins be S2. So we have 2 groups now S1(H,H,T) and S2(T,H) When we flip the selected set S1 it turns into S1F(T,T,H). We have only one head in both the sets.
Subscribe to:
Posts (Atom)
|
Popular Posts
|